JEE Main 2019 Result – National Testing Agency (NTA) will declare the JEE Main Result 2019 for the April attempt at jeemain.nic.in. The paper 1 result will be declared by April 30, 2019, and paper 2 result by May 15, 2019. NTA prepares the result by normalizing the raw scores of the candidates in the exam. There is no cut off of JEE Main, however, there is a cutoff mark to appear in JEE Advanced 2019, which announced with the JEE Main Result. This time, NTA is also releasing the JEE Main 2019 All India Rank (AIR) based on both January and April performances of the candidates. Check more details below on this page.

Latest: JEE Main 2019 Paper 1 result will be declared by April 30, 2019. However, the results are also expected to be out by this week.

JEE Main 2019 Result

JEE Main Result 2019 check is done under the candidate’s login using their application number and date of birth/password. The JEE Main 2019 Result date is as follows:

JEE Main 2019 Result April Dates
Exam date
  • 08 – 12 Apr 2019 (paper 1)
  • 07 Apr 2019 (paper 2)
Paper 1 result declaration By 30 Apr 2019
Paper 2 result declaration By 15 May 2019

Check Result: JEE Main 2019 Result Check online will be available at jeemain.nic.in

JEE Main 2019 Paper 1 Result Expected This Week

NTA has released the result of the January session within 7 days after the exam ended. In the January session, the exam ended on January 12, 2019, and the result was out on January 19, 2019. Therefore going by that trend, it is expected that after the exams ended for the April session on April 12, 2019, the results will be out this week for paper 1.

This time NTA is going to come up with the AIR and cutoff scores for JEE Advanced 2019 exam too. We are tracking the result closely, bookmark this page to get your JEE Main 2019 Result as soon as it is out.

JEE Main 2019 Paper 1 Result

What Is New About JEE Main 2019 Result This Time?

Now that the exam is over and the curiosity of the result is kicking in, here are some important things to note about your result. Check the points below:

  • In the April attempt, as many as 9.5 lakh candidates have applied for the exam and everyone will be checking their result. This is more than the January attempt
  • Not only the candidates from the April attempt are to check their result but the candidates from the January attempt are going to check their result. This is because the All India Ranks are being also declared by NTA this time.
  • All India ranks form the basis of admission in the NITs, CFTIs, and IIITs.
  • The candidates who have appeared in both their attempts will have their place in the JEE Main 2019 AIR based on their best percentile out of both the attempts.
  • Apart from the percentile scores, the result is going to have the cutoff marks for JEE Advanced 2019.

What is NTA Score On the JEE Main 2019 Result?

The NTA score or the percentile score is the normalized raw scores of the candidates. Now candidates must not confuse the percentile score with percentage. Percentile score and percentage 2 very separate values.

Difference between percentile and percentage:

  • A percentage is a number out of 100
  • However, the percentile score of a candidate reflects how many candidates have scored below that candidate in an exam. A Percentile score is a value below which a certain percent of observations fall.

How is the NTA Score (percentile score) calculated?

Now that we are clear about percentile score and percentage, now let us check how the percentile score in JEE Main 2019 is calculated. We are going to explain the process of normalization of raw scores to get the percentile score via an example below:

Say a candidate named Max appear in the JEE Main 2019 exam. He appears in the exam on April 09, 2019 and in shift 1. In shift 1 of April 09, 2019, say a total of 30,000 candidates have appeared.

Suppose Max scores a total of 300 marks out of 360 in the exam. Also, let us assume that in his shift out of 30,000 candidates 10,000 have scored equal to or less than Max. That means 10,000 candidates have scored either 300 or below 300 on April 09, 2019 in shift 1.

His total percentile score is calculated using the formula:

(100 X Number of candidates appeared in the ‘Session’ with raw score EQUAL TO OR LESS than the candidate)/Total number of aspirants who have appeared in the ‘Session’

Which means Max’s percentile score = (100X10,000)/30,000. This gives 33.3333333. Therefore Max’s total percentile score is 33.3333333. Using a similar process the percentile score of Max is calculated for each section too:

Compilation Of JEE Main 2019 April Result

Here is how the result is compiled:

  • First, the NTA scores are calculated corresponding to the raw marks obtained by a candidate in each session.
  • The calculated NTA scores for all the sessions are then merged for declaration of result.
  • The result shall comprise the four NTA scores for each of the three subjects (Mathematics, Physics, and Chemistry) and the total for the second attempt.

Compilation Of JEE Main 2019 All India Rank (AIR)

This time NTA is also releasing the AIR of the candidates. The All India Rank of the candidates is based on the best NTA scores of the candidates out of both January and April attempt. However, the candidates who have appeared in any one attempt, the AIR will be based on their NTA scores of the attempt that they have appeared in.

Here is how the AIR is compiled:

To prepare the AIR the overall Percentile score is used. If the overall percentile score of 2 or more candidates is found the same then their subject wise percentile scores are used to break the ties. Here is how the AIR is compiled:

This means that fist the total NTA score is considered. However, if 2 or more candidates get the same total percentile scores, the following inter-se-merit is to be used:

  • First, higher Percentile score in Mathematics
  • Second, higher Percentile score in Physics
  • Third, higher Percentile score in Chemistry
  • Lastlt, candidates older in age.

Opening and Closing JEE Main Ranks Of The Top NITs

In 2019, NTA is preparing the ranks based on the total NTA scores of the candidates and the institutes are to use these ranks as their opening and closing ranks for admission. As per the last years’ data, here are the opening and closing ranks of the Top NITs that accept admission based on JEE Main scores. Using them you can estimate the college you can get admission in as per your ranks in JEE Main 2019.

Name of the NIT NIRF 2019 Ranking Opening Rank Closing rank
NIT Tiruchirappalli 10 1 28966
NIT Rourkela 16 8 61490
NIT Surathkal 21 18 36842
NIT Warangal 26 10 25270
VNIT Nagpur 31 10 44982
NIT Kurukshetra 41 103 45218
NIT Durgapur 46 39 70097
MNNIT Allahabad 42 3 38648
NIT Calicut 28 27 35339
MNIT Jaipur 53 27 39165

Recommended Resource: More on top colleges and their opening and closing ranks

Keep These Information Ready To Check The JEE Main 2019 Result

Before checking the result the candidates have to take care of a few important points and they need to be ready with a few important data in order to check their result:

  1. Keep your JEE Main 2019 Application Number and date of birth handy.
  2. Stay connected to a high-speed internet connection.
  3. Also make sure you view the result in a good browser like chrome, Mozilla firefox or internet explorer 8 and above.
  4. Keep a printer ready if you wish to print your result after downloading it.

How To Check JEE Main Result 2019

To check the JEE Main 2019 Result the candidates can follow the steps below. The candidates must keep their application number as they have received at the time of registration and the above-mentioned details ready.

  • 1st Step: Click on the direct link available on this page above or visit the official website of JEE Main 2019, jeemain.nic.in.
  • 2nd Step: In doing so, the candidates have to log in using either their application number and password or the application number and date of birth.
  • 3rd Step: On entering these details the candidates are can check their scorecard on the screen.
  • 4th Step: The candidates then can download their result and print the same for future references.

Details On JEE Main 2019 Result

The result of JEE Main 2019 have the following details:

  • Application Number
  • Candidate’s Name
  • Mother’s Name
  • Father’s Name
  • Category
  • Gender
  • State Code of Eligibility
  • Roll Number
  • PwD Status
  • Date of Birth
  • Nationality
  • NTA Score in Physics, Chemistry, Maths, and Total

JEE Main 2019 Rechecking/Revaluation of Result

Note that after the result is declared the candidates are not allowed any requests of revaluation or rechecking. Once the result is out, it is the final statement of scores. NTA does not accept any revaluation or rechecking requests from the candidates. Thus, the candidates must accept their result as the final criteria based on which they are offered admission in the institutes.

After The Declaration of JEE Main 2019 Result

After the result of JEE Main 2019 is out, the candidates have to look for the centralized counselling. However, there are 2 pathways after the declaration of the result.

JEE Advanced 2019: After the declaration of the result if you qualify of JEE Advanced 2019 you can opt to register for the exam for admission in the IITs.

JoSAA Counselling: If you are not willing to participate in JEE Advanced or you have not qualified for the same you can register for the centralized counselling known as the Joint Seat Allocation Authority Counselling for admission in the NITs, IIITs, and CFTIs.

Admission Procedure to NITs, IIITs and CFTIs

The candidates are shortlisted for admission to NITs, IIITs and CFTIs by participating though Central Seat Allocation Board (CSAB). The board uses the All India Rank for admission purpose. Also, the candidate should have secured at least 75% marks in their Class 12th examination (65% in case of SC/ST), or be in the top 20 percentile in the 12th class exam conducted by the respective Boards.

Subject combinations for admission to NITs, IIITs and CFTIs

The candidates should fulfill the following condition in order to be considered for admission:

Name of the Course Subject combination in Class 12th/ Equivalent qualifying Examination
BE/ BTech Should have passed 10+2 examination with Physics and Mathematics as compulsory subjects along with one of the Chemistry/Biotechnology/Biology/ Technical Vocational subject
BArch/ B.Planning Passed 10+2 examination with Mathematics

FAQs on JEE Main 2019 Result

Ques. How are the JEE Main 2019 results announced? Are they released in the form of marks or percentile?
Ans. The result for JEE Main 2019 has been announced online in the form of percentile, i..e NTA score. Since the JEE Main exam has been in multiple sessions in multiple shifts, the method of normalization has been implied for preparing the result.

Ques. What does my JEE Mains result contain marks or percentile score?
Ans. The JEE Main 2019 result consists of the percentile score of the candidates. The AIR will be announced after the JEE Main exam for January and April session is over.

Ques. I am very confused about the raw score and percentile score. Can you please explain it in simple terms?
Ans. Raw scores are the marks obtained by the candidate in the JEE main entrance examination, whereas, the percentile score is calculated on the basis of the relative performance of all those who appear for the examination.

Ques. What is the method for calculation of NTA score?
Ans. The NTA score is not the same as the percentage, and there are various factors what are the score of the topper of your shift, total candidates appeared for your shift, etc. The percentile score basically indicates the percentage of candidates that have scored EQUAL TO OR BELOW that percentile.

The formula for calculating the percentile is as follows:

Ques. Has anyone scored a 100 percentile in JEE Main 2019?
Ans. Yes, there are about 15 students who have scored a perfect 100 percentile, and there are about 45 state-wise toppers.

Ques. How will the rank distribution approximately be according to the percentile in the JEE Mains?
Ans. The distribution of rank will be done by applying tie-breaking criteria. The AIR is going to be assigned to the candidates after January and April’s exam is over. For example – If you have obtained 60 percentile in your session and some other student has obtained 60th percentile in his/her session, then the rank is going to be assigned by applying the tie-breaking rules.

Statistics Of JEE Main 2019

National Testing Agency (NTA) has released the data of the candidates who have appeared for the April attempt and the January attempt. In the infogram below, we lay down the comparison of registrations that have been received for both April and January attempt.

JEE Main 2019 Result

JEE Main 2019 Toppers with 100 Percentile for the January Attempt

15 candidates have got a 100 percentile as per JEE Main 2019. The maximum number of candidates are from Telangana, i.e. 4. Check complete list from below:

Application No. Candidate Name State Code of Eligibility
190310086378 Dhruv Arora Madhya Pradesh
190310096437 Raj Aryan Agarwal Maharashtra
190310126508 Adelly Sai Kiran Telangana
190310131614 Bojja Chetan Reddy Andhra Pradesh
190310139257 Sambit Bheera Rajasthan
190310150035 Naman Gupta Uttar Pradesh
190310166518 Yindukuri Jayanth Phani Sai Telangana
190310167837 Vishwanth K Telangana
190310204122 Himanshu Gaurav Singh Uttar Pradesh
190310208678 Kevin Martin Karnataka
190310240908 Shubhankar Gambhir Rajasthan
190310244684 Battepati Karthikeya Telangana
190310324762 Ankit Kumar Misra Maharashtra
190310378068 Jayesh Singla Punjab
190310597090 Gupta Kartikey Chandresh Maharashtra

JEE Main January 2019 State-wise Toppers with 100 percentile

State Code of Eligibility Candidate Name NTA Score
Andaman and Nicobar Island Shusbhanshu Prasad 98.7250736
Andhra Pradesh Bojja Chetan Reddy 100.0000000
Arunachal Pradesh Prince Kumar Gupta 98.8802243
Assam Pradipta Parag Bora 99.9963677
Bihar Abhishek Kumar 99.9771914
Chandigarh Dishank Jindal 99.9972510
Chhattisgarh Rishabh Bhatnagar 99.9727580
Dadar and Nagar Haveli Vishwajeet Deshmukh 98.8751498
Daman and Diu Ashmit Singh 99.3978968
Delhi Navneet Jindal 99.9990830
Foreign / OCI / PIO / Nepal / Bhutan Ananya Amarcherla 99.8928714
Goa Jaiprakash Suresh Gurav 99.9872898
Gujarat Raghav Somani 99.9907511
Haryana Ashutosh Singla 99.9981753
Himachal Pradesh Sarthak Gupta 99.8950807
Jammu and Kashmir Aman Yadav 99.9789101
Jharkhand Ankit Kumar Jain 99.9899608
Karnataka Kevin Martin 100.0000000
Kerala Vishnu Vinod 99.9990801
Lakshadweep Abdul Javad PA 88.3358227
Madhya Pradesh Dhruv Arora 100.0000000
Maharashtra Ankit Kumar Misra 100.0000000
Maharashtra Gupta Kartikey Chandresh 100.0000000
Maharashtra Raj Aryan Agarwal 100.0000000
Manipaur Laisharam Prince Singh 97.5009989
Meghalaya Gourav Kumar 99.8872894
Mizoram Akash Jyoti Sahoo 94.5211630
Nagaland Kartikeya Chandra 96.7983937
Odisha Sibasis Nayak 99.9844902
Puducherry Chirantadip Mahanta 99.7827873
Punjab Jayesh Singla 100.0000000
Rajasthan Shubhankar Gambhir 100.0000000
Rajasthan Sambit Behera 100.0000000
Sikkim Rahul Gupta 99.1418764
Tamil Nadu Gaurav P 99.9935610
Telangana Adelly Sai Kiran 100.0000000
Telangana Yindukuri Jayanath Phani Sai 100.0000000
Telangana Battepeti Karthikeya 100.0000000
Telangana Vishwanath K 100.0000000
Tripura Shayandeep Bhaumik 99.7457412
Uttar Pradesh Himanshu Gaurav Singh 100.0000000
Uttar Pradesh Naman Gupta 100.0000000
Uttarakhand Pallav Semwal 99.9556053
West Bengal Shaswata Dutta 99.9972491

Previous Year Result Statistics for JEE Main

Last year, the exam was held at 113 exam cities for offline examination and 258 test cities for online examination.

Description Boys Girls Transgender Total
Total number of candidates registered for Paper 1 815005 32007 02 1135088
Candidates registered for offline examination 639205 258559 02 897766
Candidates registered for online examination 175800 61518 237318
Candidates appeared for offline examination 615242 247321 01 857564
Candidates appeared for online examination 161718 55039 216755
Candidates qualified for appearing in JEE Advanced 180331 50693 231024

LIST OF THE TOP 10 STUDENTS

Name of the candidate State Marks obtained AIR
Suraj Krishna Bhogi Andhra Pradesh 350 1
KVR Hemant Kumar Chodipilli Andhra Pradesh 350 2
Parth Laturia Rajasthan 350 3
Pranav Goyal Haryana 350 4
Gattu Mytraya Telangana 350 5
Pawan Goyal Rajasthan 350 6
Bhaskar Arun Gupta Rajasthan 350 7
Bakarapu Bharath Andhra Pradesh 345 8
Simranpreet Singh Saluja Delhi 345 9
Gosula Vinayak Shrivardhan Telangana 341 10

If you have any question about JEE Main 2019 Result, then do let us know in the comment section below.

JEE Main 2019

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23 COMMENTS

    • Hi Viswathika
      NTA has announced the JEE Main 2019 Jan result in form of % and the merit list will be published after Apr exam result declaration.

  1. JEE published Paper-1 Answer key to be challenged by end of day 17th Jan 2018. I have challenged 2 questions and I am sure my overall score should increase.

    To my surprise, immediately after challenge window NTA published percentile score as result. It is impossible to review all the challenges submitted by candidates overnight. This leads to following fact:

    – Final scores are yet to be calculated, post review of the challenged questions
    – Published percentile is not correct and subject to change if there is change in candidate’s score (Both up and down sides)

    I am not finding any clarity around this. Can anyone help me here please

  2. SIR…,
    What is the average percantage, for qualifying.
    So that we may have many doubts cleared….
    Please let me know SIR…..

  3. My score in April JEE Mains is 220 , Jan score was 114 . What shall be my rank now and do I stand to get any chance in Delhi ( DTU , IGIT , IIIT , NSIT ) as a girl student..thx

    • Your predicted rank in JEE Main 2019 Apr is 3314 – 4314.
      Your predicted rank in JEE Main 2019 Jan is 40815 – 45815.

      The rank should be between 2818 to 34254

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