JEE Main 2019 Result – NTA will release the JEE Main April 2019 on 15 May. Also, the combined result for both the session will release in form of merit list. The JEE Main 2019 Result releases on the official website at jeemain.nic.in. Candidates can download it using application number with password or date of birth. The JEE Main 2019 Result contains the NTA score/percentile score. AIR for JEE Main releases as per the candidate’s raw score and tie-breaker rules. Further, admission to NITs, IITs, CFITs, and SFIs will conduct on the basis of counselling round. Candidates can check JEE Main 2019 Result, details about NAT Score, JEE Main Percentile, etc from below.
JEE Main 2019 Result
The score of JEE Main are used to prepare the AIR. If the candidate appears for both JEE Main Jan and April exam then NTA will consider the best of the two scores for preparing JEE Main 2019 AIR. The application form for April exam has been released on February 08, 2019. The important dates for JEE Main 2019 Result and April exam are given below:
|JEE Main 2019 Result||January Attempt||April Attempt|
|JEE Main 2019 exam date||08 to 12 Jan 2019||07 to 20 Apr 2019|
|JEE Main 2019 Paper 2 will be held on||08 Jan 2019||–|
|Declaration of result||15 May 2019|
- Click Here to Check JEE Main 2019 Result for Paper 2.
- Click Here to Check JEE Main 2019 Result for Paper 1.
JEE Main Paper 2 Result 2019
JEE Min 2019 Paper 2 is held for B.Arch and B.Plan admission. The examination was held on January 08, 2019. The result for JEE Main 2019 Paper 2 has been announced in login. In it, NTA score of the candidates are mentioned. The exam has been topped by Gollapudi N Lakshmi Narayana and Gudla Raghunandan Reddy. Both have secured 100 percentile in the exam.
JEE Main NTA Score Calculation 2019
The new scorecard of JEE Main 2019 looks as shown below and it only contains the NTA score.
JEE Main 2019 Normalization Process Explanation
Before jumping on to any conclusion, candidates should note NTA score or the JEE Main 2019 normalized marks are not the average marks or percentage. The process of normalization is used in those exams, in which there are multiple sessions. This is done so the level of difficulty in all the sessions is the same and no candidate is at loss.
The normalization of marks is done for each session. Through it, NTA evaluates, how many candidates have performed equal to or lower than a particular candidate. To do so, following process is used.
Step 1 – Raw Score: First of all, NTA calculates the raw score of the candidates according to the marking scheme, i.e. +4 for correct answer and -1 for incorrect answer.
Step 2 – Percentile Marks / Normalized Marks / NTA Score: There is a difference in the percentage and percentile. Percentile basically describes that among all the candidates appeared for the entrance exam, what is your rank among them & where exactly do you stand.
To calculate the percentile score, NTA first determines the number of candidates that have raw score upto or below a candidate. Then it uses the formula below to evaluates the NTA Score:
Hence, in all the 8 session, the performance of the candidates is evaluated with that of the students appeared in the same session.
Example: Let us calculate Overall Normalized score of Ram.
Assumed Factor: Equal or similar number of candidates appeared for JEE Main in all the days.
- Ram appeared for Day 1 Shift 1.
- 200 candidates appeared for JEE Main Shift 1.
- Overall Raw score of Ram is 50.
- Candidates scoring (raw score) upto or below Ram in Day 1 Shift 1 are 80.
- Then, the equation will be:
Normalized Score of Ram in Day 1 Shift 1
– 100 X 80 / 200 = 40
NTA has calculate overall, as well as, subject wise normalized score of the candidate. You can check complete and detailed JEE Main 2019 Normalization process – from here.
How to Calculate Score Through JEE Main Percentile
There is no method through which candidates can calculate the result via JEE Main percentile. This is because the data for number of candidates appeared in a shift has not been announced. However, if you wish to calculate your JEE Main 2019 raw score then use the answer key of JEE Main.
The JEE Main 2019 answer key is available online. All you need to do is cross answer in answer key with that in response sheet and add 4 marks for correction option. If the answers don’t match deduct 1 marks.
JEE Main 2019 Cut Off
Now that the JEE Main 1 result has been released candidates candidates are looking for cut off. Unlike previous years, JEE Main 2019 cut off or the minimum JEE Main Marks required to qualify for JEE Advanced has not been announced with the result. Few questions that are boggling the mind of student are:
Q. What will be the JEE Main Percentile Cut Off?
A. Percentile score are not actually score but the number of candidates who scored equal or upto you. Hence, there shall not be any percentile cutoff.
Q. The cutoff for JEE Advanced will be announced as score or percentile?
A. Well, it is difficult to answer this question right now because NTA has not defined anything yet.
Q. What will be the percentile cutoff to get admission in NITs / CFTIs / XYZ college?
A. Again, the admission will be granted on the basis of JEE Main 2019 AIR. For that, you may check the closing cutoff.
You can check previous year JEE Main cutoff for JEE Advanced are as below:
|Common Rank List||74 – 350||81||100||105|
|OBC NCL||45 – 73||49||70||70|
|SC||29 – 73||32||52||50|
|ST||24 – 73||27||48||44|
|PWD||-35 – 73||01||–||–|
JEE Main 2019 Toppers with 100 Percentile
15 candidates have got a 100 percentile as per JEE Main 2019. The maximum number of candidates are from Telangana, i.e. 4. Check complete list from below:
|Application No.||Candidate Name||State Code of Eligibility|
|190310086378||Dhruv Arora||Madhya Pradesh|
|190310096437||Raj Aryan Agarwal||Maharashtra|
|190310126508||Adelly Sai Kiran||Telangana|
|190310131614||Bojja Chetan Reddy||Andhra Pradesh|
|190310150035||Naman Gupta||Uttar Pradesh|
|190310166518||Yindukuri Jayanth Phani Sai||Telangana|
|190310204122||Himanshu Gaurav Singh||Uttar Pradesh|
|190310324762||Ankit Kumar Misra||Maharashtra|
|190310597090||Gupta Kartikey Chandresh||Maharashtra|
JEE Main 2019 State-wise Toppers with 100 percentile
|State Code of Eligibility||Candidate Name||NTA Score|
|Andaman and Nicobar Island||Shusbhanshu Prasad||98.7250736|
|Andhra Pradesh||Bojja Chetan Reddy||100.0000000|
|Arunachal Pradesh||Prince Kumar Gupta||98.8802243|
|Assam||Pradipta Parag Bora||99.9963677|
|Dadar and Nagar Haveli||Vishwajeet Deshmukh||98.8751498|
|Daman and Diu||Ashmit Singh||99.3978968|
|Foreign / OCI / PIO / Nepal / Bhutan||Ananya Amarcherla||99.8928714|
|Goa||Jaiprakash Suresh Gurav||99.9872898|
|Himachal Pradesh||Sarthak Gupta||99.8950807|
|Jammu and Kashmir||Aman Yadav||99.9789101|
|Jharkhand||Ankit Kumar Jain||99.9899608|
|Lakshadweep||Abdul Javad PA||88.3358227|
|Madhya Pradesh||Dhruv Arora||100.0000000|
|Maharashtra||Ankit Kumar Misra||100.0000000|
|Maharashtra||Gupta Kartikey Chandresh||100.0000000|
|Maharashtra||Raj Aryan Agarwal||100.0000000|
|Manipaur||Laisharam Prince Singh||97.5009989|
|Mizoram||Akash Jyoti Sahoo||94.5211630|
|Tamil Nadu||Gaurav P||99.9935610|
|Telangana||Adelly Sai Kiran||100.0000000|
|Telangana||Yindukuri Jayanath Phani Sai||100.0000000|
|Uttar Pradesh||Himanshu Gaurav Singh||100.0000000|
|Uttar Pradesh||Naman Gupta||100.0000000|
|West Bengal||Shaswata Dutta||99.9972491|
JEE Main 2019 AIR Preparation Process
Since JEE Main 2019 is held twice this year, the All India Rank this year will be prepared a little differently. The process for merit calculation will be:
Compilation of January and April JEE Main 2019 Result
For attempt 1 and 2, NTA will calculate:
- Raw score of candidate.
- Percentile / normalized score of candidates in Maths
- Percentile / normalized score of candidates in Physics
- Percentile / normalized score of candidates in Chemistry
- Overall Percentile / normalized score of candidates.
Compilation of Result and Preparation of JEE Main 2019 AIR
JEE Main 2019 All India Merit List is very important. On the basis of it, admission is granted in colleges. The higher the rank, the better are the chances of admission. NTA determines JEE Main rank by following process:
Step 1 – NTA first checks if a candidates has appeared for both the session or not. If a candidates has appeared then best of both the score will be taken into consideration.
Step 2 – Next, step is to merge the percentile score of JEE Main 2019. To do, it will prepare a combine sheet in which the percentile score of candidates in all the session, and in each subject will be mentioned. It will look as shown below:
On the basis of TOTAL percentile, the JEE Main 2019 AIR will be allocated. The merit list will look as shown below:
Tie Breaker Criteria in JEE Main 2019
There is a high possibility that percentile score of two or more candidates clashes. Hence, the Agency will use the following tie breaking to evaluate the merit list of JEE Main 2019.
Tie Breaker Criteria in Paper 1 (BE /BTech)
- The candidates with higher marks in Mathematics in JEE Main will be ranked higher in the merit.
- If there is still a tie, the candidates with higher marks in Physics will be considered.
- If the tie still not resolved, the candidates who have obtained higher NTA score of the raw marks in Chemistry will be included in the merit list.
- Lastly, if the tie is still not resolved then the candidates older in age will be taken into consideration.
Tie Breaker Criteria in Paper 2 (B.Arch. /B.Planning)
- The Candidates obtaining higher marks in Aptitude Test in Paper-2 will be ranked higher in the merit.
- If there is still a tie, then the candidates obtaining higher marks in Drawing Test in Paper-2 will be given higher preference.
- if the tie is still not resolved, then the age of the candidates will be taken into consideration. Hence, the candidates older in age will be given preference over the younger candidate.
Final JEE Main 2019 Result
The final the score of JEE Main 2019 will be displayed after the April exam. The score of candidate in JEE Main Physics, Chemistry, and Mathematics in both the attempts (if appeared) will be mentioned, as follows:
How to Check the JEE Main 2019 Result?
There are two mediums through which candidates can check their JEE Main 2019 Result and these are:
- Through Application Number and Date of Birth.
- Through Application Number and Password.
How to check JEE Main 2019 Result through Application Number and Date of Birth?
Step 1 – Click on “Click Here to Check JEE Main 2019 Result via Date of Birth” link above. A new window as below will open:
Step 2 – Enter Application Number and Password to access the login.
Step 3 – On the dashboard, the scorecard will be displayed. Download it.
How to check JEE Main 2019 Result through Application Number and Password?
Step 1 – Click on “Click Here to Check JEE Main 2019 Result via Password” link above. It will lead to a window, which will appear as follows:
Step 2 – Now, the candidates need to enter Application Number and Password.
Step 3 – Following this, the dashboard will open and the scorecard will be available on it. Download JEE Main 2019 Scorecard and save it.
Details Mentioned in JEE Main 2019 Scorecard
The following details are mentioned in the scorecard of JEE Main 2019
- Application Number
- Candidate’s Name
- Mother’s Name
- Father’s Name
- State Code of Eligibility
- Roll Number
- PwD Status
- Date of Birth
- NTA Score in Physics, Chemistry, Maths, and Total
Admission Procedure to NITs, IIITs and CFTIs
The candidates are shortlisted for admission to NITs, IIITs and CFTIs by participating though Central Seat Allocation Board (CSAB). The board uses the All India Rank for admission purpose. Also, the candidate should have secured at least 75% marks in their Class 12th examination (65% in case of SC/ST), or be in the top 20 percentile in the 12th class exam conducted by the respective Boards.
Subject combinations for admission to NITs, IIITs and CFTIs
The candidates should fulfill the following condition in order to be considered for admission:
|Name of the Course||Subject combination in Class 12th/ Equivalent qualifying Examination|
|BE/ BTech||Should have passed 10+2 examination with Physics and Mathematics as compulsory subjects along with one of the Chemistry/Biotechnology/Biology/ Technical Vocational subject|
|BArch/ B.Planning||Passed 10+2 examination with Mathematics|
Re-evaluation/ Re-checking of JEE Main 2019 Result
The candidates cannot submit any request regarding the re-evaluation/ re-checking of JEE Main 2019 Result. The result once published online will be final and will not be changed.
What After the JEE Main 2019 Result is Declared?
After the declaration of JEE Main 2019 Result, the candidates will be offered admission through a Seat Allocation Process on the basis of choices filled by them and All India Rank of JEE Main 2019 Candidates shall be offered admission based on their choices and All India Ranks of JEE (Main)-2019.
At the time of the Seat Allocation process, the candidates will be able to make their choices online for branches/ programs and institutes. Also, the verification of documents would be done at the time of Seat Allocation Process/admission.
JEE Main 2019 Counselling
Joint Seat Allocation Authority (JoSAA) takes the responsibility of conducting counseling rounds for the selected candidates, every year. It is an authority which looks after smooth execution of JEE Main 2019 counseling process of seat allotment for IITs, NITs, CFTIs and other participating institutions. Counseling for participating institutions till the year 2018 has been the responsibility of JoSAA. The seat allotment is to be done on the basis of merit/rank of JEE Main 2019.
|CSAB 2019 Round 1 Counselling|
|Seat allotment result||Jun 2019|
|Reporting to center to accept seats||Jun 2019|
|Seat matrix of vacant and filled seats||Jul 2019|
|CSAB 2019 Round 2 Counselling|
|Seat allotment result||Jul 2019|
|Reporting to center to accept seats||Jul 2019|
|Seat matrix of vacant and filled seats||Jul 2019|
|CSAB 2019 Round 3, 4, 5 and other rounds of counselling|
|Seat allotment result||Jul 2019|
|Reporting to center to accept seats||Jul 2019|
|Seat matrix of vacant and filled seats||Jul 2019|
Statistics for JEE Main 2019 January Attempt
NTA has conducted JEE Main 2019 January attempt for 11,09,250 registered candidates (9,29,198 for Paper-I and 1,80,052 for Paper II). Exam took place at 9 exam centres in 4 cities in Jammu and Kashmir, and 17 exam centres in 15 cities in North-Eastern states.
Number of exam centres – 467
Cities in which JEE Main 2019 January was held – 258
Number of exam cities outside India – 9
Number of exam centres for Paper II – 390
Cities outside India in which Paper 2 was held – 6
Control Room, with
State coordinators – 25
City coordinators – 254
Observers – 566
Test Practice Centres – 4000
Number of students who used Test Practice Centres – 24000
Number of students who took JEE Main 2019 Mock Test – 25,19,290
Jammers used per shift – 4000
Previous Year Result Statistics for JEE Main
Last year, the exam was held at 113 exam cities for offline examination and 258 test cities for online examination.
|Total number of candidates registered for Paper 1||815005||32007||02||1135088|
|Candidates registered for offline examination||639205||258559||02||897766|
|Candidates registered for online examination||175800||61518||—||237318|
|Candidates appeared for offline examination||615242||247321||01||857564|
|Candidates appeared for online examination||161718||55039||—||216755|
|Candidates qualified for appearing in JEE Advanced||180331||50693||—||231024|
LIST OF THE TOP 10 STUDENTS
|Name of the candidate||State||Marks obtained||AIR|
|Suraj Krishna Bhogi||Andhra Pradesh||350||1|
|KVR Hemant Kumar Chodipilli||Andhra Pradesh||350||2|
|Bhaskar Arun Gupta||Rajasthan||350||7|
|Bakarapu Bharath||Andhra Pradesh||345||8|
|Simranpreet Singh Saluja||Delhi||345||9|
|Gosula Vinayak Shrivardhan||Telangana||341||10|
FAQs on JEE Main 2019 Result
Ques. How are the JEE Main 2019 results announced? Are they released in the form of marks or percentile?
Ans. The result for JEE Main 2019 has been announced online in the form of percentile, i..e NTA score. Since the JEE Main exam has been in multiple sessions in multiple shifts, the method of normalization has been implied for preparing the result.
Ques. What does my JEE Mains result contain marks or percentile score?
Ans. The JEE Main 2019 result consists of the percentile score of the candidates. The AIR will be announced after the JEE Main exam for January and April session is over.
Ques. What is the procedure for checking the JEE Main 2019 Result?
Ans. The candidates can check their result for JEE main 2019 online by visiting the official website at jeemain.nic.in. On the homepage of the website, the candidates need to click on the link which says “JEE (Main) January 2019 result”. On clicking the link, you will then have to log in by entering your Application Number and Date of Birth. Click on the “Login” button to submit your details and your result will be available on the screen.
Ques. I am very confused about the raw score and percentile score. Can you please explain it in simple terms?
Ans. Raw scores are the marks obtained by the candidate in the JEE main entrance examination, whereas, the percentile score is calculated on the basis of the relative performance of all those who appear for the examination.
Ques. What is the method for calculation of NTA score?
Ans. The NTA score is not the same as the percentage, and there are various factors what are the score of the topper of your shift, total candidates appeared for your shift, etc. The percentile score basically indicates the percentage of candidates that have scored EQUAL TO OR BELOW that percentile.
The formula for calculating the percentile is as follows:
Ques. Has anyone scored a 100 percentile in JEE Main 2019?
Ans. Yes, there are about 15 students who have scored a perfect 100 percentile, and there are about 45 state-wise toppers.
Ques. How will the rank distribution approximately be according to the percentile in the JEE Mains?
Ans. The distribution of rank will be done by applying tie-breaking criteria. The AIR is going to be assigned to the candidates after January and April exam is over. For example – If you have obtained 60 percentile in your session and some other student has obtained 60th percentile in his/her session, then the rank is going to be assigned by applying the tie-breaking rules.
If you have any question about JEE Main 2019 Result, then do let us know in the comment section below.