JEE Main 2020 Result – NTA has finally announced JEE Main result for B.Arch and B.Plan paper as well. Candidates can check it from the login, by entering application number and date of birth. The result for B.Tech / B.E paper has already been announced. The result of JEE Main is available as scorecard, in which details of candidates and NTA score in each section and overall is given. Check JEE Main 2020 result for B.Arch, B.Plan, B.Tech / B.E from this page.
Latest: Check your JEE Main 2020 result using the direct link below. Also, have you applied for WBJEE 2020? Admit Card for it has been released.
JEE Main 2020 Result
In the Jan exam 8,69,010 candidates took the B.E / B.Tech paper. Top 2.5 lakh candidates of JEE Main 2020, on the basis of AIR, shall be eligible for JEE Advanced 2020 exam. The all India rank and cut off for JEE Advanced is released after the April exam, taking into consideration the best NTA score of the candidates out of both the attempts. For important dates of JEE Main 2020 result check the table below.
|JEE Main 2020 result||January dates||April dates|
|JEE Main 2020 exam date||05, 07, 08, 09, and 11, 2020|
|Declaration of result||30 Apr 2020|
|JEE Main B.Arch and B.Plan result date||23 Jan 2020||–|
Check here: Click here to check and download JEE Main 2020 result.
JEE Main 2020 Result January Notification (B.Arch and B.Plan): Candidates can check and download press release for JEE Main B.Arch and B.Plan result from below.
JEE Main 2020 Result January Notifications (B.Tech / B.E): National Testing Agency has published notifications with the result of JEE Mains conveying how many candidates appeared in exam, who are the toppers, and so on.
How to Check JEE Main Result 2020?
To check the result for Joint entrance examination (JEE) Main-2020, follow the simple instructions as provided below.
Step 1: Click on the direct link on this page to check JEE Main result.
Step 2: Through the direct link, candidates can directly access the result login.
Step 3: Candidates need to provide application number, date of birth ant appear on the screen.
Step 4: Next, click on the ‘submit’ button.
Step 5: On submitting the login details, your result appears on the screen.
Step 6: Lastly, download and take a print out of the scorecard for future reference.
Forgot JEE Main 2020 Login Details? Get here
In case if you do not remember JEE Main 2020 login details, then you can retrieve it by simply following the instructions as provided below.
How to Get Application Number for JEE Main Login?
To get the application number for JEE Main candidate login, follow these steps:
Step 1: Click here in case if you forgot JEE Main application number.
Step 2: On clicking the direct link, a login page appears in which you need to provide your name, father’s name, mother’s name, and date of birth.
Step 3: After this, click on the “get application number” button to submit the details and then your application number will appear on the screen.
JEE Main 2020 Toppers
A total of 869010 candidates appeared for BE / BTech exam out of which a total of 09 students obtained perfect 100 percentile. Check the name of the 100 percentiles in JEE Main Jan 2020 exam below.
|Name of the 100 percentiler||State of eligibility|
|Landa Jitendra||Andhra Pradesh|
|Thandavarthi Vishnu Sri Sai Sankar||Andhra Pradesh|
|Nishant Agarwal||Delhi (NCT)|
|Rongala Arun Siddardha||Telangana|
|Chagari Koushal Kumar Reddy||Telangana|
JEE Main Jan 2020 State wise list of 100 percentilers
|State code of eligibility||Candidates name||NTA score|
|Andaman and Nicobar islands||Akshat Singh||97.3286395|
|Andhra Pradesh||Landa Jitendra||100.0000000|
|Andhra Pradesh||Thadavarthi Vishnu Sri Sai Sankar||100.0000000|
|Arunachal Pradesh||Apurba Nath||96.1831211|
|Chandigarh||Kunwar Preet Singh||99.9972380|
|Dadra and Nagar Haveli||Sharad Vishwakarma||99.2655484|
|Daman and Diu||Jain Anmol Rajesh Kumar||98.6482824|
|Delhi (NCT)||Nishant Agarwal||100.0000000|
|Himachal Pradesh||Sarthak Diwan||99.9683001|
|Jammu and Kashmir||Aryan Gupta||99.7338263|
|Madhya Pradesh||Akarsh Jain||99.9959069|
|Maharashtra||Vedang Dhirendra Asgaonkar||99.9972435|
|Meghalaya||P Alias Chakma||96.3974118|
|Odisha||Sourabh Soumyakanta Das||99.9924070|
|Outside India||Nilay Mankala||99.5839421|
|Tamil Nadu||Gaurav R Kochar||99.9959069|
|Telangana||Rongala Arun Siddardha||100.0000000|
|Telangana||Chagari Koushal Kumar reddy||100.0000000|
|Uttar Pradesh||l Gokulnath||99.9993050|
|West Bengal||Sreemanti Dey||99.9923468|
JEE Main 2020 Rank Predictor
You can know the expected JEE Main rank predicted in advance through this easy tool called JEE Main Rank Predictor. The Rank Predictor of JEE Main involves very simple steps to get an estimate on what would be the possible rank of the candidates in JEE Main 2020 Exam.
Candidates are required to know or have an idea about the marks likely to be fetched in Board exam and in JEE Main. Students may use the JEE Main answer key to know their JEE Main score.
Click Here to use JEE Main 2020 Rank Predictor
Details Given on JEE Main 2020 Scorecard
The scorecard for JEE Main 2020 consist of the following information:
- Application number
- Roll number
- candidate’s name
- Mother’s name
- Father’s name
- PwD status
- Date of birth
- Subject wise NTA score
- Overall NTa score
- NTA score in words
- Important instructions
Sample of JEE Main Scorecard
Components of JEE Main 2020 Result
For a multiple-shift entrance examination, the conducting body declares the result by applying the process of Normalisation. It is used to ensure that candidates are not at disadvantage due to any difference in difficulty level of exam shift and session. Hence, to overcome such a situation, “Normalization procedure based on Percentile Score” is used. In this process, candidate scores across multi session papers are compared and based on it percentile score is used.
JEE Main result 2020 is prepared as follows:
Raw scores – It is the marks obtained by the candidate based on the marking scheme released by NTA. For a correct answer, 04 marks are given and 01 marks are deducted for an incorrect response. NTA does not disclose the raw score but determines it on the basis of final answer key.
Formula to calculate JEE Main Raw Score
JEE Main Raw Score = 4 x Number of Correct Answers – 1 X Number of Incorrect Answers
JEE Main AIR – The All India Rank for JEE Main 2020 is prepared on the basis of JEE Main Jan / April exam. If the candidate has appeared for both the exams then the best percentile score is used for allocating rank to the candidates.
Percentile score – It is prepared by normalizing raw score of the candidates. It indicates the percentage of candidates who have scored equal to less than you in the entrance exam. The percentile score is further used for preparation of the merit lists. The percentile score is calculated using the formula:
100 x Number of candidates appeared in the ‘session’ with raw score equal to or less than the candidate / Total number of the candidates appeared in the ‘session’
How is JEE Main 2020 Result Prepared?
The result of JEE Main 2020 is prepared by first calculating the raw scores, then by turning it into normalized marks and then by determining rank on the basis of the percentile score. The step-by-step process for normalisation and preparation of JEE Main merit list is explained below:
Step 1: Distribution of examinees
- The examinees are distributed in four sessions randomly so that each session has an approximate equal number of candidates.
- In case of more number of days or more number of shifts, candidates are divided accordingly.
Step 2: Preparation of result for each session
- NTA prepares JEE Main result in the form of a raw score, percentile score separate for each subject, and total percentile.
Step 3: Compilation of NTA score and preparation of overall merit list
- The percentile score for all the session is merged together to get NTA score which is then further used for the preparation of overall merit / rank list.
- Tie-breaker criteria is used in case of two or more candidates obtain equal percentile.
JEE Main 2020 Result Compilation for both the Attempts
NTA prepares the overall merit list / ranking for JEE Main first and second attempt by merging the four NTA scores (Total, Physics, Chemistry and Mathematics) for each of the candidate. Those who appeared in both the attempts, their best of the two NTA scores is considered further for preparation of the merit list / ranking.
Tie Breaker Policy for JEE Main 2020
In case of two or more candidates obtain equal percentile in the exam, their tie is resolved by applying the following methods:
- Candidates with a higher percentile score in Mathematics is ranked higher in the merit.
- If there is still a tie, then the candidates with higher percentile score in Physics are given preference in the merit.
- If the tie still persists, then the higher percentile score in Chemistry is cosidered for breaking the tie.
- If none of the above methods resolve the tie, then the age of the candidate is taken into consideration. Candidate older in age is preferred in the merit.
What After JEE Main Result 2020 is Declared?
After the declaration of JEE Main 2020 result, candidates have two options. They can either opt to appear for JEE Advanced 2020 or opt for JoSAA counselling. Candidates can check more information on both these options below:
About JEE Advanced 2020 – IIT Delhi is organising JEE Advanced 2020 for admission in various programs at IITs. The exam is going to be conducted on May 17, 2020, in two shifts.
About JoSAA Counselling – Joint Seat Allocation Authority conducts counselling to allot seats to the candidates in 23 IITs, 31 NITs, 25 IIITs and 28 Other-Government Funded Technical Institutes (Other-GFTIs). For JoSAA counselling, candidates need to register first online, choose the options for course and colleges and finally based on JEE Main rank, they are allotted a college.
JEE Main 2020 Cutoff Marks
The cut off marks for JEE Main is the minimum qualifying marsk required by the candidate to be eligible to participate for JEE Advanced 2020. It is generally released with the declaration of the result. One important thing to note is that there is no minimum cut off marks required to qualify JEE Main, whereas, the cut off is to proceed to appear for JEE Advanced. Until, JEE Main 2020 result is declared, candidates can check the previous cut off marks from below.
JEE Main cut off for the year 2019:
|Category||JEE Main Cut Off|
|Common Rank List||89.7548849|
JEE Main Opening and Closing Rank
In the table below, we have provided opening and closing rank for the top NITS as per NIRF ranking 2019. It has been prepared based on previous year information and will be updated as soon as JoSAA counselling starts.
|Name of the NIT||Opening Rank||Closing rank|
|Motilal Nehru National Institute of Technology||05||32077|
JEE Main All India Rank (AIR)
The All India Rank (AIR) is an important component of JEE Main result as it is used for admissions through Central Seat Allocation Board (CSAB)/Joint Seat Allocation Authority (JoSAA) to NITs/ IIITs/ CFTIs/ SFIs/ Others. It is released after the declaration of JEE Main April 2019 result. JEE Main AIR is printed on the scorecard for April exam and is prepared based on final NTA score. Other than IITs/ NITs, etc, other enginerring colleges uses AIR for preparation of their separate merit list for shortlisting of candidates.
JEE Main 2020 April Result
Likewise, for April attempt, NTA score is calculated for each session as per the normalization process. After this, the calculated NTA score is merged for preparation of JEE Main April result. It comprises of subject-wise NTA score and total percentile in the second attempt. JEE Main April result is released under candidate login. Along with the NTA score, All India Rank (AIR) is also released. Candidates who appeared for both the attempts, their best of two NTA score is used for the preparation of JEE Main list.
JEE Main 2020 Counselling
NTA Is responsible for only conducting the exam and handing over the result to the concerned authorities. The JoSAA counselling is conducted by Joint Seat Allocation Authority (JoSAA). It is conducted in online mode for admissions in IITs, NITs, IIEST, IIITs and Other-GFTIs. Candidates who appear for JEE Main 2020 are eligible to register for JoSAA 2020 counselling and those who have been declared qualified in JEE (Adv) 2020 are also eligible to register for counselling.
JoSAA counselling process includes filling in of choices, locking of choices, seat allotment, acceptance / rejection of seat. KLast yer, about 107 institutes participate in JoSAA counselling which included 23 IITs, 31 NITs, 25 IIITs and 28 Other-Government Funded Technical Institutes (Other-GFTIs.
JEE Main 2020 Statistics
Candidates can check the data for JEE Main 2020 for paper 1 and paper 2 from the table below. The data provided below as per the unofficial sources and will be updated with the press release by NTA.
|Particulars||JEE Main 2020 Jan||JEE Main 2020 Apr|
|Total number of Registered candidates||9,21,261 – B.E/B.Tech|
1.38 lakh – Paper 2
|Will be notified later|
|Total number of candidates appeared in exam||B.E/B.Tech – 8,69,010||Will be notified later|
|Total number of female candidates||2,64,026||Will be notified later|
|Total number of male candidates||6,04,981||Will be notified later|
|Total number of Transgender candidates||3||Will be notified later|
About JEE Main 2020
Joint Entrance Examination (JEE Main) is a national level test being conducted by the National Testing Agency (NTA) from the year 2019 onwards. The exam is conducted twice a year ever since NTA took the responsibility of conducting. First, it is held in the month of January and then in the month of April. Through JEE Main score, candidates are offered admission in NITs, IIITs, and the CFTIs. Furthermore, JEE Main score is also accepted by various Private engineering institutes like Amrita university, UPES, etc for admission in engineering programs.
The National Testing Agency (NTA) is a government-approved agency which has a purpose to conduct various entrance examinations nationwide. It was established in November 2017. NTA conducts various national level exam like NEET-UG, CMAT, GPAT, etc for admission in engineering, medical, management, pharmacy courses and recruitment tests like CSIR-NET, UGC-NET for college / university teaching and fellowship.
JEE Main 2020 Previous Year Toppers
Check below the list of last year toppers of JEE Main 2020
|Application number||Candidate name||State code of eligibility|
|190310086378||Dhruv Arora||Madhya Pradesh|
|190310096437||Raj Aryan Agarwal||Maharashtra|
|190310126508||Adelly Sai Kiran||Telangana|
|190310131614||Bojja Chetan Reddy||Andhra Pradesh|
|190310150035||Naman Gupta||Uttar Pradesh|
|190310166518||Yindukuri Jayanth Phani Sai||Telangana|
|190310204122||Himanshu Gaurav Singh||Uttar Pradesh|
|190310324762||Ankit Kumar Misra||Maharashtra|
|190310597090||Gupta Kartikey Chandresh||Maharashtra|
JEE Main 2020 Result Frequently Asked Questions
Ans : There is a normalization process. The formula used to normalize the score is available in the information brochure of JEE Main.
Ans : No. The counselling process is independent of NTA. Thus there is no change in JoSAA.
Ans : Class 12th boards Result only certifies the candidate’s eligibility for the exam. However, for taking admission to NITs, IIITs and CFTIs are based on All India Rank as explained above along with at least 75% marks in the 12th class exam or be in the top 20 percentile in the 12th class examination conducted by the respective Boards.
Ans : The candidates have to register for the JoSSA counselling at the official JoSSA website jossa.nic.in in order to be able to fill their choice of institutes in order of preference to be eligible for participating in admission counselling.
Ans : No, the JEE Main Results declared by NTA after the publishing of the Answer Key will be final and binding.
Ans : The candidates can retrieve their Application Number and Password by pressing the i can’t access my account button and select the option of forgot password or application number button. After filling in details like registered email, date of birth and father’s name, the candidate will be able to retrieve the application number and reset their password.
Ans : The process of normalization helps in creating a uniform and just parameter of judgment for all the candidates who give the exam in a different session. To give an equal opportunity to all the candidates the process of normalization has been introduced in the declaration of the JEE Main 2020 Result.
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