JEE Main 2019 – National Testing Agency (NTA) will be conducting JEE Main 2019 Jan exam between January 06 to 20, 2019. The examination will be held in online mode, in multiple slots, across 261 cities. The application process for exam has ended and the registered candidates can download the JEE Main admit card from December 17, 2019. NTA releases the admit card through login, on jeemain.nic.in. It can be downloaded from the link on this page. JEE Main 2019 is an entrance exam for admission in B.Tech / B.E / B.Arch / B.Plan courses, offered by the NITs, GFTIs, IIITs, and other government and private colleges. Top qualifiers of Joint Entrance Examination 2019 will be called for JEE Advanced. Check information on JEE Main 2019 hall ticket, dates, exam pattern, syllabus, and more from this page.
JEE Main 2019
NTA is conducting JEE Main 2019 twice. Once it will be held in the month of January 2019, and for it 9.5 lakh candidates have applied. Then, JEE Main April 2019 will be held. It will also be held online. In the April examination
|Particulars||JEE Main I 2019 Exam Date||JEE Main II 2019 Exam Dates|
|Registration for TPCs starts on||01 Sep 2018||08 Feb 2019|
|JEE Main application form availability||01 Sep 2018||08 Feb 2019|
|Last date to apply for the exam||30 Sep 2018||07 Mar 2019|
|Downloading of JEE Main 2019 admit card starts from||17 Dec 2018||18 Mar 2019|
|JEE Main 2019 will be held on||06 to 20 Jan 2019||06 to 20 Apr 2019|
|JEE Main 2019 Paper 2 will be held on||08 January 2019|
|Answer key will be uploaded on||Jan 2019||Apr 2019|
|Result will be announced on||31 Jan 2019||20 Apr 2019|
JEE Main 2019 Admit Card
JEE Main 2019 admit card is an important document. To download it, application number and password is required. The candidates can only download it through the official login, available at jeemain.nic.in. Hard copy of it will not be send to the candidate’s postal address. The admit card of JEE Main 2019 holds details such as the name of candidates, date of birth, center code, center address, date of exam, timing, etc.
Along with the admit card, the candidates will have to carry:
- A photo id proof – it can be Aadhaar Card, Voter Id Card, College ID, Passport, Bank Passbook with Photo, etc.
- PwD certificate if claiming relaxation under PwD category.
JEE Main 2019 Mock Test by NTA
National Testing Agency (NTA) has released the mock test for JEE Main 2019. Candidates can take this test to practice and well versed with the upcoming exam. As the exam will happen twice in a year and will be conducted by NTA, so candidates can take this test to familiar with the questions and pattern. The link to take the mock test is provided below.
Mock Test: Click Here to take the JEE Main 2019 Mock Test.
JEE Main 2019 Syllabus
There will be no difference in the syllabus of JEE Main 2019. Candidates will still get question from:
Mathematics – Sets, Number System, Complex Numbers & Qadratic Equation, Permutation & Combination, Mathematical Induction, Binomial Theorem, Sequencers & Series, Limit, Continuity & Differentiability, Integral Calculus, etc.
Physics – Physics & Measurement, Kinematics, Laws of Motion, Work, Energy & Power, Rotational Motion, Gravitation, Properties of Solids and Liquids, Thermodynamics, Kinetic Theory of Gases, etc.
Chemistry – Basic Concepts of Chemistry, States of Matter, Atomic Structure, Chemical Bonding & Molecular Structure, Chemical Thermodynamics, Solution, Equilibrium, etc.
- The candidates can download the detailed syllabus of JEE Main 2019 – From Here
JEE Main 2019 Exam Pattern
As NTA has made clear, JEE Main 2019 exam pattern will remain the same as before candidates may check it from below:
JEE Main 2019 Exam Pattern for Paper 1 –
Duration: Candidates will get 3 hours to give JEE Main 2019 I and II. Exam will be held in 2 shifts and timing will be informed through admit card.
Language: The language of the exam will be English, Hindi, Gujarati.
Exam Mode: JEE Main 2019 will only be held in online mode.
Total Number of Questions: In all there will be 90 questions in the exam. 30 questions in each section.
Type of Questions: All questions will be of Multiple Choice Type. NTA will give 4 answer choices for each question and only 1 will be correct.
Marks Per Questions: 4 marks for each question. No mark will be allocated or deducted for unattended questions.
Negative Marking: 1 mark will be deducted for wrong answer. This is applicable in all the sections.
Total Marks: The exam will be of total 360 marks.
Check marks and question distribution in JEE Main 2019 from below:
JEE Main 2019 Exam Pattern for Paper 2 –
Duration: Candidates will 3 hours to attempt the exam.
Languages: The language of the exam will be English, Hindi, Gujarati.
Exam Mode: Mathematics (part I), aptitude test (part II) will be computer based tests. Drawing test (part III) will be pen and paper based test.
Total Number of Questions: In all, there will be 82 questions.
Types of Question: Maths and General Aptitude will be MCQ based, whereas, in Drawing Skill candidates will have to show their drawing skills.
Marks Per Questions: 4 marks for each MCQ. Drawing test will be of more marks. No marks for unattempted questions.
Negative Marking: NTA is going to deduct 1 marks for negative marking in MCQs.
Total Marks: 390.
Check the distribution of question and from the table below:
JEE Main 2019 Question Paper
Candidates look for question paper after the exam. Since, NTA is going to conduct JEE Main 2019 in multiple session and days the candidates will definitely try and find the question paper. But, let us make it clear that this year it will be difficulty to find the JEE Main question paper. Such is because NTA hold the exam online and will ensure that the questions are repeated in the exam.
Level of question papers: To conduct the exam, NTA will prepare a very large pool if questions. However, it will also ensure that the level of each question paper should be same as other one. Out of syllabus or questions with too much variation in difficulty will not bne asked.
JEE Main 2019 Answer Key
Till the time Central Board of Secondary Education (CBSE) was conducting Joint Entrance Examination Main, it released the answer key for the offline, as well as the online exam. So, even if now NTA will only hold the exam in online mode candidates can still look forward to release of answer key. Candidates can get the answer key of JEE Main 2019 from nta.ac.in. Candidates will be able to download it from the login and maybe able to to challenge it.
The JEE Main 1 answer key will be released for both Paper 1 and Paper 2. The candidates will be able to check answers through it and predict their score in the exam. Due to online exam, coaching institutes and unofficial bodies might not be able to release the answer key. Yet, the candidates may rely on the memory based key to evaluate their performance in the exam.
JEE Main 2019 Cut Off
Cut off is the minimum marks that a candidate should secure to qualify an exam. However, the last rank at which a college grants admission is also known as the cutoff. Hence, we have mentioned below both the JEE Main cutoff for the exam held last year:
JEE Main Cutoff for JEE Advanced was as follows: There is no cut off for JEE Main. But in the scorecard, a cutoff is available and it for JEE Advanced. For JEE Advanced, those candidates qualify who score more than the cutoff. In the previous year it was as follows:
|Last Year’s JEE Main Cut Off for JEE Advanced|
|Category||Minimum Marks||Maximum Marks|
|OBC – NCL||45||73|
In the previous year, the cut off to be qualified for JEE Advanced exam was as follows:
JEE Main Closing Rank Cut Off: The closing for each college differs. Candidates can check it for each college From Here
What to Expect from JEE Main 2019 Cut Off – It is too early to expect anything from NTA. As per the policies of NTA the pattern and syllabus of the exam will is not changing. Hence, there is a possibility that the cut off will also remain the same.
Yet, there can be a difference in the cut off. The basis for determining the JEE Main cut off are – the number of applicants, level of difficulty, number of seats, etc. When all of this details will be clear, then one can predict the cut off for the exam.
JEE Main 2019 Result
NTA will announce result of JEE Main I 2019 on nta.ac.in. The candidates will get to know their score and all India rank through it. On the basis of it, JoSAA will call candidates for counselling and seat allotment.
Return of Normalization in JEE Main 2019 Result? – Yes, as predicted, NTA is reintroducing normalization in JEE Main 2019. It is because NTA is conducting exam online and in multiple sessions. Now, to ensure that the level of the exam is same throughout and no candidate is at disadvantage, it is implementing normalization.
Will Class 12th Marks Used in Result Calculation? – NTA has made clear that it will not use class 12th marks for score or JEE Main 2019 rank calculation. But the marks of class 12th are an important criteria for admission.
JEE Main 2019 Counselling
Just like last year, Joint Seat Allocation Board (JoSAA) will hold the counselling for JEE Main 2019. NITs, IIITs, and GFTIs will participate in it. The number of institute that appeared for the counselling last time is as follows:
- National Institute of Technology (NITs) – 31
- Indian Institute of Information Technology (IIITs) – 23
- Government Funded Technical Institutes (GFTIs) – 23
Other that this, there are numerous other institutes which consider the score of JEE Main. In the counselling seat allocated on the basis of JEE Main AIR.
JEE Main 2019 Test Practice Centers (TPC)
For Joint Entrance Examination Main 2019 NTA has decided to established 2,697 Test Practice Centers (TPC). Through these test centers, candidates can learn and understand how the JEE Main 2019 online exam will be. Also, candidates can practice for the examination and score better marks.
For JEE Main 2019 TPC registration can be done from September 01, 2018. Candidates must not miss this opportunity and do register it. The registration is to be done at nta.ac.in.
- Click Here to check the notice regarding TPC.
JEE Main 2019 Application Form and Correction
JEE Main 2019 Application Form Correction facility has ended. The application correction process ended on due date. Candidates could edit almost all the details other than exam centre. The candidates who wished to change the category and paper had to pay more application fee.
Candidates who are eager to know the application process, may read below.
JEE Main 2019 Application Form was available at jeemain.nic.in. Candidates had to upload photograph and signature in the application form. Other than that, the candidates also had to update Aahdaar Card details in the form.
How to Apply for JEE Main 2019? – To apply for JEE Main 2019, candidates first had to register. To do so, state of eligibility, class 12 state, identification type, identification number, name of candidate, date of birth, gender are needed. Once registered, candidates will get registration number and password. With these details, candidates need to login and fill the application form of JEE Main 2019.
JEE Main 2019 Application Fee: New application fee for JEE Main I and II are:
- Boys of General/OBC category appearing either Paper 1 or Paper 2: Rs 500
- Girls of any category or SC/ST/PWD / Transgender appearing either Paper 1 or Paper 2: Rs 250
- Boys of General/OBC category appearing in both Paper 1 and Paper 2: Rs 900
- Girls of any category or SC/ST/PWD / Transgender appearing in both Paper 1 and Paper 2: Rs 450
Candidates can submit the amount of fee online, through Net Baking, Debit Card, Credit Card, e challan.
JEE Main 2019 Eligibility Criteria
It is important to satisfy the eligibility criteria of JEE Main 2019. It is as follows:
Age Criteria – To appear for JEE Main 2019, candidates should have passed, or will pass, class 12 exam in 2017, 2018 or 2019.
Education Qualification – Candidates should have passed class 12th from a recognized institute, with at least 5 subjects.
“No candidate shall be admitted to architecture course unless she/he has passed an examination at the end of the 10+2 scheme of examination with 50% marks in Physics, Chemistry and Mathematics and also 50% marks in aggregate of the 10+2 examination”. Click here to check detailed notice.
Top 20 Percentile or 75% Marks Criteria – To get admission through JEE Main 2019, candidate should be among 20 percentile in the class 12th Board exams or must have got above 75%. SC / ST candidates need to get more than 65% marks in Boards exams.