JEE Main 2019

JEE Main 2019 – Application form of JEE Main 2019 has been released by NTA at jeemain.nic.in instead of nta.ac.in. Candidates can apply online with documents required and pay fee before last date. Joint Entrance Examination (JEE) Main is one of the biggest engineering exam of India. Earlier CBSE conducted JEE but now National Testing Agency (NTA) will hold it. JEE Main 2019 will be held twice, first attempt from 6 to 20 January 2019, and second attempt from 6 to 20 April 2019, both for B.Tech / B.E / B.Arch / B.Plan admission to NITs, GFTIs, IIITs, and other government and private colleges. Top qualifiers will be called for JEE Advanced, which is held for IITs admission. Candidates can check JEE Main 2019 complete details including pattern, news, syllabus pdf, eligibility, date, official website, application form, admit card, result, cut off.

JEE Main 2019 Latest News

In this section, we will keep on updating all the latest information about JEE Main 2019. The latest so far are:

September 11, 2018 – The Aadhaar number is only one of the types of identification and is not mandatory, check notice.
September 8, 2018
 – JEE Main 2019 Official Mock Test available now. Also, the notice regarding TPC has published, check below.
September 6, 2018
 – Those who are facing difficulty in making payment through online mode, are advised to make the payment through e-challan. Check detailed notice
September 1, 2018
 – JEE Main 2019 Application Form is available. Apply now!
August 29, 2018 – JEE Main 2019 Mock Test available at Aglasem.com.

JEE Main 2019

NTA is conducting JEE Main 2019 I (first attempt) and II (second attempt). Both times, there will be Paper 1 for B.Tech and B.E admission, and, JEE Main Paper 2 for B.Arch and B.Plan admission.

What is JEE Main I 2019 – NTA JEE Main I 2019 is the exam that will be held in the month of January 2019

What is JEE Main II 2019 – On the other hand, NTA JEE Main II 2019 which will be conducted in the month of April 2019 is being referred to as JEE Main II 2019. Dates for both the exams are as follows:

Particulars JEE Main I 2019 Exam Date JEE Main II 2019 Exam Dates
Registration for TPCs starts on 01 Sep 2018 08 Feb 2019
JEE Main application form availability 01 Sep 2018 08 Feb 2019
Last date to apply for the exam 30 Sep 2018 07 Mar 2019
Issuance of admit card will begin in 17 Dec 2018 18 Mar 2019
JEE Main 2019 will be held on 06 to 20 Jan 2019 06 to 20 Apr 2019
Answer key will be uploaded on Jan 2019 Apr 2019
Result will be announced on 31 Jan 2019 20 Apr 2019

JEE Main 2019 Mock Test

National Testing Agency (NTA) has released the mock test for JEE Main 2019. Candidates can take this test to practice and well versed with the upcoming exam. As the exam will happen twice in a year and will be conducted by NTA, so candidates can take this test to familiar with the questions and pattern. The link to take the mock test is provided below.

Mock Test: Click Here to take the JEE Main 2019 Mock Test.

JEE Main 2019 Test Practice Centers (TPC)

For Joint Entrance Examination Main 2019 NTA has decided to established 2,697 Test Practice Centers (TPC). Through these test centers, candidates can learn and understand how the JEE Main 2019 online exam will be. Also, candidates can practice for the examination and score better marks.

For JEE Main 2019 TPC registration can be done from September 01, 2018. Candidates must not miss this opportunity and do register it. The registration is to be done at nta.ac.in.

JEE Main 2019 Application Form

JEE Main 2019 Application Form is available at jeemain.nic.in. Candidates have to upload photograph and signature in the application form. Other than that, the candidates also have to update Aahdaar Card details in the form. Hence, keep it ready before filling the form.

How to Apply for JEE Main 2019? – To apply for JEE Main 2019, candidates first have to register. To do so, state of eligibility, class 12 state, identification type, identification number, name of candidate, date of birth, gender are needed. Once registered, candidates will get registration number and password. With these details, candidates need to login and fill the application form of JEE Main 2019.

JEE Main 2019 Application Fee: New application fee for JEE Main I and II are:

  • Boys of General/OBC category appearing either Paper 1 or Paper 2: Rs 500
  • Girls of any category or SC/ST/PWD / Transgender appearing either Paper 1 or Paper 2: Rs 250
  • Boys of General/OBC category appearing in both Paper 1 and Paper 2: Rs 900
  • Girls of any category or SC/ST/PWD / Transgender appearing in both Paper 1 and Paper 2: Rs 450

Candidates can submit the amount of fee online, through Net Baking, Debit Card, Credit Card, e challan.

JEE Main 2019 Eligibility Criteria

It is important to satisfy the eligibility criteria of JEE Main 2019. It is as follows:

Age Criteria – To appear for JEE Main 2019, candidates should have passed, or will pass, class 12 exam in 2017, 2018 or 2019.

Education Qualification – Candidates should have passed class 12th from a recognized institute, with at least 5 subjects.

Top 20 Percentile or 75% Marks Criteria – To get admission through JEE Main 2019, candidate should be among 20 percentile in the class 12th Board exams or must have got above 75%. SC / ST candidates need to get more than 65% marks in Boards exams.

JEE Main 2019 Admit Card

To download JEE Main admit card 2019, application number and password will be needed. The candidates will only get through the login and will have to carry it as a print copy on the exam day. The admit card of JEE Main 2019 will hold details such as the name of candidates, date of birth, center code, center address, date of exam, timing, etc.

Along with the admit card, the candidates will have to carry:

  • A photo id proof – it can be Aadhaar Card, Voter Id Card, College ID, Passport, Bank Passbook with Photo, etc.
  • PwD certificate if claiming relaxation under PwD category.

JEE Main 2019 Syllabus

There will be no difference in the syllabus of JEE Main 2019. Candidates will still get question from:

Mathematics –  Sets, Number System, Complex Numbers & Qadratic Equation, Permutation & Combination, Mathematical Induction, Binomial Theorem, Sequencers & Series, Limit, Continuity & Differentiability, Integral Calculus, etc.

Physics – Physics & Measurement, Kinematics, Laws of Motion, Work, Energy & Power, Rotational Motion, Gravitation, Properties of Solids and Liquids, Thermodynamics, Kinetic Theory of Gases, etc.

Chemistry – Basic Concepts of Chemistry, States of Matter, Atomic Structure, Chemical Bonding & Molecular Structure, Chemical Thermodynamics, Solution, Equilibrium, etc.

  • The candidates can download the detailed syllabus of JEE Main 2019 – From Here

JEE Main 2019 Exam Pattern

As NTA has made clear, JEE Main 2019 exam pattern will remain the same as before candidates may check it from below:

JEE Main 2019 Exam Pattern for Paper 1 –

Duration: Candidates will get 3 hours to give JEE Main 2019 I and II. Exam will be held in 2 shifts and timing will be informed through admit card.

Language: The language of the exam will be English, Hindi, Gujarati.

Exam Mode: JEE Main 2019 will only be held in online mode.

Total Number of Questions: In all there will be 90 questions in the exam. 30 questions in each section.

Type of Questions: All questions will be of Multiple Choice Type. NTA will give 4 answer choices for each question and only 1 will be correct.

Marks Per Questions: 4 marks for each question. No mark will be allocated or deducted for unattended questions.

Negative Marking: 1 mark will be deducted for wrong answer. This is applicable in all the sections.

Total Marks: The exam will be of total 360 marks.

Check marks and question distribution in JEE Main 2019 from below:

Section Question Marks
Physics 30 120
Chemistry 30 120
Mathematics 30 120
Total 90 360

JEE Main 2019 Exam Pattern for Paper 2 –

Duration: Candidates will 3 hours to attempt the exam.

Languages: The language of the exam will be English, Hindi, Gujarati.

Exam Mode: Mathematics (part I), aptitude test (part II) will be computer based tests. Drawing test (part III) will be pen and paper based test.

Total Number of Questions: In all, there will be 82 questions.

Types of Question: Maths and General Aptitude will be MCQ based, whereas, in Drawing Skill candidates will have to show their drawing skills.

Marks Per Questions: 4 marks for each MCQ. Drawing test will be of more marks. No marks for unattempted questions.

Negative Marking: NTA is going to deduct 1 marks for negative marking in MCQs.

Total Marks: 390.

Check the distribution of question and from the table below:

Sections Question Marks
Mathematics 30 120
General Aptitude 50 200
Drawing Skill 2 70
Total 82 390

JEE Main 2019 Question Paper

Candidates look for question paper after the exam. Since, NTA is going to conduct JEE Main 2019 in multiple session and days the candidates will definitely try and find the question paper. But, let us make it clear that this year it will be difficulty to find the JEE Main question paper. Such is because NTA hold the exam online and will ensure that the questions are repeated in the exam.

Level of question papers: To conduct the exam, NTA will prepare a very large pool if questions. However, it will also ensure that the level of each question paper should be same as other one. Out of syllabus or questions with too much variation in difficulty will not bne asked.

JEE Main 2019 Answer Key

Till the time Central Board of Secondary Education (CBSE) was conducting Joint Entrance Examination Main, it released the answer key for the offline, as well as the online exam. So, even if now NTA will only hold the exam in online mode candidates can still look forward to release of answer key. Candidates can get the answer key of JEE Main 2019 from nta.ac.in. Candidates will be able to download it from the login and maybe able to to challenge it.

The JEE Main 1 answer key will be released for both Paper 1 and Paper 2. The candidates will be able to check answers through it and predict their score in the exam. Due to online exam, coaching institutes and unofficial bodies might not be able to release the answer key. Yet, the candidates may rely on the memory based key to evaluate their performance in the exam.

JEE Main 2019 Cut Off

Cut off is the minimum marks that a candidate should secure to qualify an exam. However, the last rank at which a college grants admission is also known as the cutoff. Hence, we have mentioned below both the JEE Main cutoff for the exam held last year:

JEE Main Cutoff for JEE Advanced was as follows: There is no cut off for JEE Main. But in the scorecard, a cutoff is available and it for JEE Advanced. For JEE Advanced, those candidates qualify who score more than the cutoff. In the previous year it was as follows:

Last Year’s JEE Main Cut Off for JEE Advanced
Category Minimum Marks Maximum Marks
ST 24 73
SC 29 73
OBC – NCL 45 73
General 74 350
PwD -35 73

In the previous year, the cut off to be qualified for JEE Advanced exam was as follows:

JEE Main Closing Rank Cut Off: The closing for each college differs. Candidates can check it for each college From Here

What to Expect from JEE Main 2019 Cut Off – It is too early to expect anything from NTA. As per the policies of NTA the pattern and syllabus of the exam will is not changing. Hence, there is a possibility that the cut off will also remain the same.

Yet, there can be a difference in the cut off. The basis for determining the JEE Main cut off are – the number of applicants, level of difficulty, number of seats, etc. When all of this details will be clear, then one can predict the cut off for the exam.

JEE Main 2019 Result

NTA will announce result of JEE Main I 2019 on nta.ac.in. The candidates will get to know their score and all India rank through it. On the basis of it, JoSAA will call candidates for counselling and seat allotment.

Return of Normalization in JEE Main 2019 Result? – Yes, as predicted, NTA is reintroducing normalization in JEE Main 2019. It is because NTA is conducting exam online and in multiple sessions. Now, to ensure that the level of the exam is same throughout and no candidate is at disadvantage, it is implementing normalization.

Will Class 12th Marks Used in Result Calculation? – NTA has made clear that it will not use class 12th marks  for score or JEE Main 2019 rank calculation. But the marks of class 12th are an important criteria for admission.

JEE Main 2019 Counselling

Just like last year, Joint Seat Allocation Board (JoSAA) will hold the counselling for JEE Main 2019. NITs, IIITs, and GFTIs will participate in it. The number of institute that appeared for the counselling last time is as follows:

  • National Institute of Technology (NITs) – 31
  • Indian Institute of Information Technology (IIITs) – 23
  • Government Funded Technical Institutes (GFTIs) – 23

Other that this, there are numerous other institutes which consider the score of JEE Main. In the counselling seat allocated on the basis of JEE Main AIR.

Official Website : nta.ac.in, jeemain.nic.in.

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