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Solutions Notes for NEET and JEE Main 2027: Key Points and PDF

Conducted by NTA Scope National

Solutions is Chapter 1 of NCERT Class 12 Chemistry Part I and forms Unit 5 of Physical Chemistry in both the NEET UG and JEE Main syllabus. These notes cover concentration terms, solubility and Henry’s law, Raoult’s law, ideal and non-ideal solutions, azeotropes, the four colligative properties and the van’t Hoff factor, with a free notes PDF.

Solutions Notes for NEET and JEE Main

Section-wise key points from NCERT Chapter 1, formula and comparison tables, high-yield facts and common mistakes for 2027 revision.

Solutions at a Glance

ItemDetails
Exams that cover itNEET UG and JEE Main (both 2026 syllabi)
Syllabus unitPhysical Chemistry, Unit 5: Solutions (same unit number in both syllabi)
NCERT textbookChemistry Part I, Class 12, Chapter 1 (rationalised book)
Syllabus topicsConcentration terms (molality, molarity, mole fraction, percentage by volume and mass); vapour pressure of solutions and Raoult’s law; ideal and non-ideal solutions; vapour pressure-composition plots; colligative properties; molar mass from colligative properties; abnormal molar mass and van’t Hoff factor
Official chapterNCERT Chapter 1
Notes PDFView PDF

The topic list follows the NEET UG 2026 syllabus (NMC public notice dated 22 December 2025) and the JEE Main 2026 syllabus published by NTA, which stay the reference until the 2027 versions are out. The full lists are on the NEET syllabus and JEE Main syllabus pages. Henry’s law, azeotropes and reverse osmosis are in the NCERT chapter but are not named separately in the syllabus text.

What is a solution and what types are there?

A solution is a homogeneous mixture of two or more components; the component present in the largest amount is usually the solvent, and it decides the physical state of the solution.

Type of solutionSoluteSolventNCERT example
GaseousGasGasMixture of oxygen and nitrogen
GaseousLiquidGasChloroform mixed with nitrogen
GaseousSolidGasCamphor in nitrogen
LiquidGasLiquidOxygen dissolved in water
LiquidLiquidLiquidEthanol dissolved in water
LiquidSolidLiquidGlucose dissolved in water
SolidGasSolidHydrogen in palladium
SolidLiquidSolidAmalgam of mercury with sodium
SolidSolidSolidCopper dissolved in gold
  • Brass is copper + zinc, German silver is copper + zinc + nickel, and bronze is copper + tin.
  • 1 ppm fluoride in water prevents tooth decay, while 1.5 ppm causes mottled teeth.

How is the concentration of a solution expressed?

Mass percentage, ppm, mole fraction and molality do not depend on temperature; molarity does, because volume changes with temperature.

TermFormulaExample from NCERT
Mass % (w/w)Mass of component ÷ total mass of solution × 100Commercial bleach has 3.62% sodium hypochlorite by mass
Volume % (V/V)Volume of component ÷ total volume × 10035% (v/v) ethylene glycol antifreeze lowers the freezing point of water to 255.4 K
Mass by volume % (w/V)Mass of solute in 100 mL of solutionUsed in medicine and pharmacy
Parts per millionParts of component ÷ total parts × 10^6Used for trace amounts, e.g. pollutants or dissolved O2 in sea water
Mole fraction (x)Moles of component ÷ total moles; sum of all x = 120% ethylene glycol by mass: x(glycol) = 0.068
Molarity (M)Moles of solute ÷ volume of solution in litres5 g NaOH in 450 mL: 0.278 M
Molality (m)Moles of solute ÷ mass of solvent in kg1.00 m KCl: 74.5 g KCl in 1 kg water

Solubility and Henry’s Law

Solubility is the maximum amount of a substance that dissolves in a specified amount of solvent at a given temperature; for gases, Henry’s law links it to pressure.

  • ‘Like dissolves like’: polar solutes dissolve in polar solvents and non-polar solutes in non-polar solvents.
  • A saturated solution is in dynamic equilibrium with undissolved solute (dissolution and crystallisation at equal rates).
  • Solid in liquid: if dissolution is endothermic, solubility rises with temperature; if exothermic, it falls (Le Chatelier). Pressure has no significant effect, since solids and liquids are nearly incompressible.
  • Gas in liquid: solubility increases with pressure and decreases with temperature, because dissolving a gas is exothermic.
  • Henry’s law: at constant temperature the solubility of a gas is proportional to its partial pressure; commonly p = KH x.
  • A higher KH means lower solubility. KH of N2 and O2 rises with temperature, which is why aquatic species are more comfortable in cold water.
Application of Henry’s lawExplanation
Soft drinks and soda waterBottles are sealed under high pressure to increase CO2 solubility
Bends in scuba diversHigh pressure dissolves more N2 in blood; on rising, N2 bubbles block capillaries. Tanks use air diluted with helium (11.7% He, 56.2% N2, 32.1% O2)
Anoxia at high altitudeLower partial pressure of O2 gives low blood oxygen, making climbers weak and unable to think clearly

Vapour Pressure and Raoult’s Law

Raoult’s law: for a solution of volatile liquids, the partial vapour pressure of each component is directly proportional to its mole fraction in the solution.

  • p1 = p1° x1 and p2 = p2° x2, where p° is the vapour pressure of the pure component.
  • Dalton’s law: ptotal = p1 + p2 = p1° + (p2° − p1°) x2, so ptotal varies linearly with x2.
  • Vapour composition: pi = yi ptotal. The vapour is always richer in the more volatile component.
  • NCERT example: CHCl3 (200 mm Hg) and CH2Cl2 (415 mm Hg) at 298 K give ptotal = 347.9 mm Hg, with y(CH2Cl2) = 0.82 in the vapour.
  • Raoult’s law is a special case of Henry’s law in which KH equals p1°.
  • A non-volatile solute lowers the vapour pressure of the solvent, because solute particles occupy part of the surface. The lowering depends on the amount of solute, not its nature: 1 mol sucrose and 1 mol urea in 1 kg water give nearly the same lowering.
  • Raoult (French chemist) gave the law in 1886.

What is the difference between ideal and non-ideal solutions?

Ideal solutions obey Raoult’s law at all concentrations; non-ideal solutions show positive or negative deviations depending on whether A–B attractions are weaker or stronger than A–A and B–B.

FeatureIdealPositive deviationNegative deviation
Raoult’s lawObeyed over the entire rangeVapour pressure higher than predictedVapour pressure lower than predicted
A–B interactionsNearly equal to A–A and B–BWeaker than A–A or B–BStronger than A–A and B–B
ΔmixH and ΔmixVBoth zeroNot zeroNot zero
Examplesn-Hexane + n-heptane; bromoethane + chloroethane; benzene + tolueneEthanol + acetone (acetone breaks H-bonds of ethanol); carbon disulphide + acetonePhenol + aniline; chloroform + acetone (hydrogen bond between them)
Azeotrope formed if deviation is largeNoneMinimum boiling azeotropeMaximum boiling azeotrope
  • Azeotropes are binary mixtures with the same composition in liquid and vapour that boil at constant temperature, so they cannot be separated by fractional distillation.
  • Minimum boiling example: ethanol-water; fractional distillation stops at about 95% ethanol by volume.
  • Maximum boiling example: nitric acid-water, about 68% HNO3 and 32% water by mass, boiling at 393.5 K.

Colligative Properties and Molar Mass

Colligative properties depend on the number of solute particles relative to the total, not on their identity: relative lowering of vapour pressure, elevation of boiling point, depression of freezing point and osmotic pressure.

PropertyFormulaMolar mass of solute
Relative lowering of vapour pressure(p1° − p1)/p1° = x2 (≈ n2/n1 for dilute solutions)M2 = w2 M1 p1° ÷ [w1 (p1° − p1)]
Elevation of boiling pointΔTb = Kb mM2 = 1000 w2 Kb ÷ (ΔTb w1)
Depression of freezing pointΔTf = Kf mM2 = 1000 w2 Kf ÷ (ΔTf w1)
Osmotic pressureΠ = CRT = (n2/V) RTM2 = w2 RT ÷ (Π V)
  • Kb (ebullioscopic constant) and Kf (cryoscopic constant) have the unit K kg mol–1 and depend only on the solvent: Kf = R M1 Tf² ÷ (1000 ΔfusH) and Kb = R M1 Tb² ÷ (1000 ΔvapH).
  • Water: Kb = 0.52 and Kf = 1.86 K kg mol–1. Benzene: Kb = 2.53 and Kf = 5.12 K kg mol–1 (NCERT Table 1.3).
  • A solution of 1 mol sucrose in 1000 g water boils at 373.52 K at one atmosphere.
  • A solution freezes when its vapour pressure equals that of the pure solid solvent, which happens at a lower temperature.

Osmosis, Osmotic Pressure and Reverse Osmosis

Osmosis is the flow of solvent through a semipermeable membrane from pure solvent (or dilute solution) into the more concentrated solution; osmotic pressure is the excess pressure that just stops it.

  • Semipermeable membranes may be natural (pig’s bladder, parchment) or synthetic (cellophane).
  • Osmotic pressure is the preferred method for molar masses of proteins, polymers and other macromolecules: it is measured near room temperature, uses molarity, and is large even for very dilute solutions.
  • Isotonic solutions have the same osmotic pressure; no osmosis occurs between them.
  • Blood cell fluid is isotonic with 0.9% (mass/volume) NaCl, called normal saline. Above 0.9% (hypertonic) cells shrink; below 0.9% (hypotonic) they swell.
  • Everyday examples: raw mangoes shrivel in brine, wilted flowers revive in fresh water, salty food causes edema, and salting meat or sugaring fruit kills bacteria by osmosis.
  • Reverse osmosis: a pressure larger than the osmotic pressure pushes pure solvent out of the solution. It is used to desalinate sea water with a cellulose acetate membrane, which lets water through but not ions and impurities.

Abnormal Molar Masses and the Van’t Hoff Factor

Dissociation increases the number of particles and gives a lower experimental molar mass; association reduces it and gives a higher one. The van’t Hoff factor i corrects for this.

  • i = normal molar mass ÷ abnormal molar mass = observed colligative property ÷ calculated colligative property = total moles of particles after ÷ before association or dissociation.
  • Van’t Hoff introduced the factor in 1880.
  • i > 1 for dissociation (KCl in water is close to 2); i < 1 for association (ethanoic acid in benzene is nearly 0.5, because it dimerises by hydrogen bonding in a solvent of low dielectric constant).
  • Modified equations: ΔTb = i Kb m, ΔTf = i Kf m, Π = i n2RT/V, and relative lowering of vapour pressure = i n2/n1.
Salti at 0.1 mi at 0.001 mi for complete dissociation
NaCl1.871.972.00
KCl1.851.982.00
MgSO41.211.822.00
K2SO42.322.843.00

Most-asked Facts for NEET and JEE Main: Solutions

Revise these one-line facts from the NCERT chapter just before the exam.

  • Molarity depends on temperature; molality, mole fraction, mass % and ppm do not.
  • Henry’s law: p = KH x; higher KH means lower gas solubility.
  • Gas solubility in liquids falls as temperature rises.
  • Scuba tanks: 11.7% He, 56.2% N2, 32.1% O2 to avoid bends.
  • Raoult’s law for a non-volatile solute: relative lowering of vapour pressure = mole fraction of solute.
  • Ideal solution: ΔmixH = 0 and ΔmixV = 0; e.g. benzene + toluene.
  • Positive deviation: ethanol + acetone; negative deviation: chloroform + acetone, phenol + aniline.
  • Large positive deviation gives a minimum boiling azeotrope (ethanol-water, about 95% ethanol).
  • Large negative deviation gives a maximum boiling azeotrope (HNO3-water, 68% HNO3, 393.5 K).
  • Kb of water = 0.52 K kg mol–1; Kf of water = 1.86 K kg mol–1.
  • Π = CRT; osmotic pressure is used for molar masses of proteins and polymers.
  • 0.9% (mass/volume) NaCl is normal saline, isotonic with blood cells.
  • Reverse osmosis uses a cellulose acetate membrane to desalinate sea water.
  • i is close to 2 for KCl in water and nearly 0.5 for ethanoic acid in benzene.
  • Dissociation lowers, association raises the experimentally found molar mass.

Common Mistakes to Avoid

Watch for these mix-ups when you answer questions on this chapter.

  • Using litres of solution for molality. Molality uses kilograms of solvent; molarity uses litres of solution.
  • Thinking a larger Henry’s law constant means higher solubility. It means lower solubility.
  • Saying gas solubility increases with temperature. It decreases, since dissolution of a gas is exothermic.
  • Swapping the azeotrope types: positive deviation gives a minimum boiling azeotrope, negative deviation a maximum boiling one.
  • Calling chloroform + acetone a positive deviation. Hydrogen bonding between them makes it negative.
  • Using molality in the osmotic pressure formula. Π = CRT uses molarity.
  • Writing i > 1 for association. Association gives i < 1 and a higher apparent molar mass.
  • Saying the vapour above a solution has the same composition as the liquid. It is richer in the more volatile component (except for an azeotrope).
  • Mixing up hypertonic and hypotonic: cells shrink in a hypertonic solution (above 0.9% NaCl) and swell in a hypotonic one.

Download the AglaSem notes for Solutions (key notes and important questions with answers) free: View PDF

Chemistry Notes for NEET and JEE Main: All Chapters

All chapters with key points and notes PDFs are on the Chemistry notes for NEET and JEE Main page.

Solutions Notes for NEET and JEE Main FAQs

Which NCERT chapter is Solutions?
It is Chapter 1 of the NCERT Class 12 Chemistry Part I textbook (rationalised book). In both the NEET UG and JEE Main syllabus it is Unit 5 of Physical Chemistry.
Is Solutions in the NEET 2027 and JEE Main 2027 syllabus?
It is in the latest NEET UG syllabus (2026, NMC notice of 22 December 2025) and the JEE Main 2026 syllabus as Unit 5. NMC and NTA have not released 2027 syllabi yet; check this page and the syllabus pages once they are out.
What is the difference between molarity and molality?
Molarity is moles of solute per litre of solution and changes with temperature because volume does. Molality is moles of solute per kilogram of solvent and does not depend on temperature, which is why it is used for boiling and freezing point calculations.
Why does the van’t Hoff factor differ from 1?
When a solute dissociates (like KCl) the number of particles rises and i is more than 1; when it associates (like ethanoic acid dimerising in benzene) the number falls and i is less than 1. Colligative properties change by the same factor.
Are these notes enough for Solutions questions?
No. Read NCERT Chapter 1 fully and work through its solved examples on concentration terms, Raoult’s law and colligative properties, because numericals from this chapter need practice. Use these notes and the PDF for revision, then solve previous year questions.
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